$5\:+\:3x\:>\:2\left(3x\:-2\right)$
$-9x-3$
$\frac{dy}{dx}=-8x+9x^2$
$\frac{dy}{dx}\left(3x-\tan\left(y\right)-4\right)$
$\sin2x\cdot\tan x=2\sin^2x$
$\int_0^{2\pi}\:\:\frac{1}{4}cos^6xdx$
$100x^6+60x^3y^4+9y^8$
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