$sin\:t=\frac{2}{3}$
$10r\:+\:42\:=\:-38$
$\left(7x-6y\right)\left(7x+6y\right)$
$x^2-8x+40$
$\frac{dy}{dx}=2\sin\left(x\right)\left(y-3\right)$
$\lim_{x\to1}\left(\frac{1-\cos\left(x-1\right)}{ln^2x}\right)$
$4x-2y=1$
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