$4x^3-9x^5$
$\frac{12x+4y}{6xy}$
$\lim_{x\to infinity}\left(846\left(\frac{2}{3}\right)^x\right)-\left(396\left(\frac{1}{3}\right)^x\right)$
$\left(m+19\right)\left(m+10\right)$
$\left(6a\:+\:9b\right)^3$
$-6+4-3-2-8+5$
$a^2=9x^2$
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