$\frac{a^4-16}{a^2+4\:}$
$\lim_{x\to0}\left(ae^x\right)$
$\left(5x^2-3y\right)\left(2x^2+y\right)$
$\lim_{x\to0}\left(\frac{x-xcos\left(7x\right)}{\left(sin\left(16t\right)\right)^2}\right)$
$7x^{3}+3x^{2}$
$3 ^ { \prime } ( - 3 ) 3 = 6$
$43.00+16.00+7.00+1.8$
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