$\lim_{x\to0}\left(\frac{1-\cos\left(6x\right)}{3x^2}\right)$
$a^3+a^2+a$
$\frac{\left(2x^2+14x+20\right)}{x+4}$
$4+\frac{x+5}{x-4}>6+\frac{1}{x-4}$
$a^2-9a+16$
$5\cdot0-6$
$x-26<14$
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