$-6\left(8+4+3\right)$
$\left(x-8y\right)^3$
$\frac{x^6}{x}$
$\left(4\sqrt{9}+3\sqrt{25}\right)+\left(11\sqrt{4}-9\sqrt{4}\right)$
$\left(x^2+y\right)^5$
$x^4-7+\frac{16}{x^4}$
$\frac { x ^ { 3 } - 3 } { x }$
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