$xydy=1+x^2dx$
$8z+12+3$
$\left(6x-\frac{1}{3}y\right)\left(6x+\frac{1}{6}y\right)$
$9\infty$
$-20^2$
$\int\frac{arctan\left(x^2\right)}{x}dx$
$\frac{1}{4x}-\frac{3}{4}=\frac{7}{x}$
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