$\frac{d}{dx}y=8x^{-4}$
$xy'\:+2y\:=3$
$-18-\left(-19\right)$
$\int\:\frac{\left(2-x\right)^2}{x^3}dx$
$\int3a^xdx$
$sen\left(x^3\right)-2sen\left(x^2\right)cos\left(x^2\right)$
$3x^2+5y^3=1$
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