$6\tan b-3=\tan b-8$
$3y\:-2xy;\:x=2;y=-1$
$\int\frac{5}{x^2+3x-41}dx$
$a\left(a^2+3-a\right)$
$\frac{x-4}{x+5}<4$
$4x+7\le2x-7$
$35.\left(-5\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!