$\frac{10z^5}{\left(5z^3\right)^2}$
$\int\left(\frac{t^4}{t^2-1}\right)dt$
$\left(3a\left(x-4\right)+b\left(3x\right)\right)\left(3a\left(x-3\right)-b\left(3x\right)\right)$
$1-sen^2x=1$
$x^8-10x^4+25$
$-8x\:-3\:x\:-4\:$
$xy^2dy+\left(x^2+1\right)dx=0$
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