$2\left(y+3\right)+6\left(y-4\right)+5$
$3\sqrt{c}-1=\sqrt{c}+1$
$65\cdot17$
$x^2-3x-18>0$
$3x-2-3\left(-1+2x\right)=2-2\left(x-1\right)$
$\frac{6}{x^2-2x-8}$
$0.19+3.18+0.723+0.1314$
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