$\frac{\left(1-cos\left(4x\right)\right)}{2}=sin^4x$
$\frac{\left(x^3y\right)^2}{y^{-4}y^{-2}y^4}$
$8x\left(x^2y^2+x^2+y^2+1\right)dx=7y\left(x^2+1\right)dy$
$\int\frac{4x}{\sqrt{2x^2-5}}dx$
$x^2-11x-37=0$
$\left(5n\right)^2-5n^2$
$z^2+12z+36$
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