$\int\sin^3\left(4f\right)df$
$0x\:\left(-7\right)$
$\frac{dy}{dx}=e^{4u+9t}$
$204.76\cdot0.95$
$2\left(5x-3\right)+3\left(10x^2-x\right)-3\left(4x+1\right)$
$\left(m^{10}-2n\right)^2$
$logx^2=logx$
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