$\lim_{n\to0}\left(n+\sqrt[3]{n^2-n^3}\right)$
$x-2y+3z=1$
$\left(\frac{\frac{\cos\left(x\right)}{\sin\left(x\right)}}{\cos\left(x\right)}\right)^2=\csc\left(x\right)^2$
$-8\cdot4\cdot4$
$8x^2+x^2-3x^2-2x^5+6x^5$
$27d^2+36d$
$7.40+3.25+1.7$
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