$\sqrt[6]{-17}$
$\left(-3\frac{2}{3}\right)^2$
$y'=y+8$
$\frac{x}{3}=-3$
$\sin\left(a\right)-\sin\left(a\right)\cos^2\left(a\right)=\sin\left(a\right)^3$
$-2\left(x+4y\right)\left(2x-3y\right)$
$\left(\left(-b\right)^3\right)^5$
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