$\int\frac{tan^2x}{sec^2x}dx$
$\frac{4x-20}{10}\:-\frac{x+2}{3}\le14$
$2\sqrt{-108}$
$\frac{dy}{dx}=\frac{2x^3}{2y+1}$
$3+6:\left(-3\right)$
$61\cdot98$
$-11f-3$
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