$\frac{sen\left(x\right)}{\cos\left(x\right)}-\frac{\cos\left(x\right)}{1+\sin\left(x\right)}=\tan\left(x\right)$
$x^2-5x-28$
$\frac{8}{\left(5x-4\right)\left(5x+4\right)}$
$-21\::\:\left(-2-5\right)\:+\:\left(-14\right)\:+\:6\:.\:\left(8\:-\:4\:.\:3\right)$
$x^2-8x+16=64$
$\left(5x-2x^3-4x^2-2\right)+\left(x^4+2x^3-x^5+5\right)$
$\left(4y-5x\right)^3$
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