$\int\frac{sec^2x}{tanx\left(tanx+1\right)}dx$
$\frac{dy}{dx}\left(2+3x\right)^{\frac{2}{x}}$
$\tan\left(x+15\right).\cot\left(y-45\right)=1$
$\left(x+2\:\right)^4\:\left(x-3\right)+7\:x+1$
$-\frac{-8}{-2}$
$\frac{cosx}{cot^2x}$
$\frac{1}{x}\frac{dy}{dx}+3x^2y^2=0$
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