$\lim x\to0\frac{\left(\cos\left(2x\right)-1\right)}{e^x-x-1}$
$3\:sen\:x\:-\:cos2\:x\:-\:3\:=\:0$
$\frac{8x^5+4x^3+5x^2+8x+16}{2x^3+x^2+3}$
$144a^2-96a+16$
$256m^2-9$
$\left(-42\right).\left(+0\right)$
$\left(\frac{x+4}{3\left(\left(x+4\right)-3\right)}\right)$
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