$\int\frac{2x^2-6x+8}{\left(x-3\right)\left(x-2\right)^2}dx$

$13.07-\frac{1}{3}$

$\int\left(\left(3\sin\:\left(x\right)\right)\sqrt{1+cosx}\right)dx$

$\int\cos\left(\frac{\left(2x-3\right)}{5}\right)dx$

$x^2-8xy+16y^2$

$\lim_{x\to2}\left(4x^2-8x+5\right)$

$\frac{2x^4-3x^3+6x-8}{x^2-2}$