$\left(x^2\right)\left(x+3\right)$
$\lim_{x\to\infty}\left(\frac{4x^3}{e^{5x}}\right)$
$7\cdot74$
$\int\frac{2t^2-8t-8}{\left(t-2\right)\left(t^2-4\right)}dt$
$x\:\left(x+18\right)$
$5\left(x+-1\right)=2\left(x+2\right)$
$6x^2+7x-20$
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