$16a^2-40a+25$
$\left(-\:4\right)\:.\:2\:+\:8\::\:\left(\:-\:2\right)$
$3r+10r$
$2\left(3m-5\right)$
$+4\cdot\left(-3\right)\cdot\left(+6\right)$
$\frac{-i+5i}{2}$
$\int_1^{\infty}\left(\frac{1}{x^2+6}\right)dx$
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