$\int\:\left(x+8\right)^3dx$
$\int\left(0.04t+200\right)e^{-0.04t}dt$
$\left(x^2+4y\right)^3$
$\sqrt[3]{24\left(x+1\right)^8z^2}$
$\frac{2^2+2z-3}{z+3}$
$\frac{d^2y}{dx^2}\:-4\frac{dy}{dx}\:+13y\:=\:0$
$\frac{66}{a}=-11$
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