$\tan x=9$
$\log\:_{\frac{1}{3}}\left(3x+1\right)=\log\:_{\frac{1}{3}}\left(x-1\right)$
$x+3\sqrt{x}-4=0$
$logx=8$
$\int3\sin^4\left(5x\right)dx$
$\frac{dn}{dt}=nte^{t+8}$
$\sqrt[3]{a^6\cdot b^4}$
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