$xy'+\frac{y}{2}=0$
$\left(2a^4+3b^5\right)\left(2a^4-3b^5\right)$
$\int10xe^{x^2+1}dx$
$\int\frac{1}{\left(b+x\right)^2}dx$
$18x-6x^2+12=-420$
$\left(4.4^5\right)^3$
$\:\:\frac{5^3}{5^{-1}}$
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