$3x^3-6x+27x^2$
$h+7+2h+8$
$-9+7w+2$
$\left(\frac{\left(4\right)}{\left(5a\right)}\right)+\left(\frac{\left(2\right)}{\left(6a\right)}\right)$
$\frac{34}{4}-\frac{1}{4}-\frac{1}{4}$
$a^2\int dx$
$\sqrt[3]{125x^3}$
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