$-3a^3\left(2a^2-5a^4\right)$
$5x-1=x+27$
$3x-15<9$
$\tan^{-1}\left(3x\right)=3$
$\frac{x^5-3x^3-6x^2+7}{x-1}$
$p\left(t\right)=\frac{1}{5}\left(1-p\left(t\right)\right)$
$\lim_{x\to4}\frac{x^2-x-56}{x-8}$
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