$\frac{dy}{dx}-8y=6$
$\cos\left(x\right)+\cos\left(x\right)\cdot\frac{\sin\left(x\right)^2}{\cos\left(x\right)^2}=\frac{1}{\cos\left(x\right)}$
$12.005\cdot2$
$\left(6b-5\right)\left(b+1\right)$
$\:-\:6-\:3-\left(-6\:+\:9\:\right)\:+\:15\:\:-\:12$
$\int\frac{\cos4x}{2+\sin4x}dx$
$-20\cdot10$
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