$\lim_{x\to\infty}\left(\frac{x^4-4x^3}{4}\right)$
$\frac{dy}{dx}=\frac{xy+y^2}{x^2+3xy}$
$-2x^3-y-2z^2+4x^3-2y+3z^2$
$y\:=\:3x^{-x}$
$\sqrt{54y^8}$
$2\cos\left(0\right)-\sqrt{3}$
$-\left(2x-3\right)\left(x-1\right)$
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