$7x+3x\left(x-4\right)$
$\frac{dv}{dt}+\frac{v}{10}=5$
$6^{x+3}=-1$
$2n^2\:+\:7n\:-92=8$
$+7\:-\:\left[\:+1\:-\:\left(\:+10\:\right)\::\:\left(\:+5\:\right)\:\right]\:$
$2^{\infty}$
$\lim_{x\to6}\sqrt{4x-3}$
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