$2-1.4$
$0>2x^2+6x+3$
$\left(2x+3y^3\right)\left(2x-3y^3\right)$
$\left(10d-h\right)^2$
$\frac{x^2}{x-3}>=x+1$
$2x^2\:-3x\:=4$
$-2z\:-\:1\:=\:6z\:+\:47$
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