$\left(\frac{3}{4}m\right)\left(\frac{2}{5}m^5x\right)\left(\frac{7}{6}x^3y\right)$
$\frac{dy}{dx}=\:y^3$
$sen^2a\left(1-sen\:a\right)$
$2x^3+x^2-4x-3$
$\left(x^3+y\right)^2$
$-27-\left(-17\right)-\left(-34\right)-16$
$\frac{dy}{dx}\left(x^2+2x^3y^2=y^2+2\right)$
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