$\log\left(x+3\right)^4=12$
$2x^2+3x+17>0$
$3x+16=-50$
$\frac{9m^2n}{-4mn^2}$
$-5n+4n-7=8$
$\left(\frac{-48ab^3}{-6a^3b^5}\right)^{-1}$
$\frac{1}{x^{-2}}$
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