$3x^{2}+x-4=0$
$x^3+2<0$
$7-3\cdot1$
$\left(\frac{1}{x}\left(x-1\right)\right)^5$
$\lim_{x\to-\infty}\left(8x\cdot\sqrt{x^2+x}-8x^2\right)$
$10x^2-13x-3$
$\frac{8x^3-125}{2x-5}$
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