$\lim_{n\to\infty}\left(\frac{\sqrt{n+2}}{\frac{1}{\sqrt{n}}}\right)$

$\left(34\right)-\left(-26\right)$

$\left(-34\right)\left(48\right)$

$\left(\sec\left(x\right)+\tan\left(x\right)\right)^2=\frac{\sec\left(x\right)+\tan\left(x\right)}{\sec\left(x\right)-\tan\left(x\right)}$

$y^9+27$

$n^2-3n+28=0$

$\left(5b^2\right)^{-3}$