$\left(-+1\right)^2$
$4xy-2x^2y=2\left(x-xy\right)$
$\frac{dy}{dx}=2xy=4x$
$\frac{2}{3}\left(4x+9\right)$
$\int tan^3\left(x\right)\cdot sec^{\frac{3}{2}}x\:dx$
$\frac{1}{\tan^{2}x}$
$\left(6-3\right)+\left(4\cdot9\right)$
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