$6\left(-4\:-\:3q\right)$
$\int\frac{2\left(x^2+8\right)}{x^3+4x}dx$
$8p^2+40p+10$
$\int_1^2\left(3x-7\right)\left(x-3\right)dx$
$\left(-6\right)\left(-5\right)\left(-3\right)\left(4\right)\left(-3\right)\left(-5\right)$
$\left(-3m^2+5n^3\right)\left(3m^2+5n^3\right)$
$7 - ( x ^ { 3 } ) ^ { 2 }$
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