$\frac{3x^2+5x^1-4}{x+3}$
$\left(x^2-49\right)+\left(x-7\right)$
$\left(4x-5\right)\left(x+3\right)$
$x^2+14x-196$
$3x^2\:\frac{dx}{dy}=2$
$49y^4-25$
$\frac{1}{4}\log_b\left(y\right)+7\log_b\left(x\right)-\log_b\left(w\right)$
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