$\left(3+4x-x^2\right)\left(x^3-2x^2\right)$
$\lim_{x\to\infty}\left(4^{\frac{x+2}{x+1}}\right)$
$8y^21+36y+4$
$8,31-6,03$
$\frac{4^{3x+1}}{2x-1}=16^{x+1}$
$\frac{d}{dx}\left(sin^2\left(e^{sin^2\left(t\right)}\right)\right)$
$\frac{1}{16}\int\cos^3\left(x\right)dx$
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