$3x^2-42=0$
$20.3\frac{3}{4}$
$\int12x\:in\left(3x\right)dx$
$\left(6u^2+5v\right)^3$
$\frac{dy}{dx}\left(\left(1-4x\right)tanh^{-1}\left(4x\right)\right)$
$\frac{151x+1}{5}-\frac{1}{3}$
$18-\left(-5\right)$
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