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$\:\:\:\:\:\:-8\:\:+\:\:\:\:\:\:-1\:\:\:\:\:-\:\:\:-64\:\:\:-\:\:\:\:12$
$\int\frac{x^2}{\left(4-x^3\right)^2}dx$
$\frac{3}{x}=\frac{2}{x-1}$
$\left(5m-8b\right)^2$
$-8-\left(-17\right)$
$\cos\cdot\tan+1-\cos=\sin$
$-\left(-2x\right)\left(\frac{1}{3}x^3+5x^2\right)$
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