$\left(4x+\frac{3}{7}\right)\left(4x-\frac{3}{7}\right)$
$2a+8b-4c$
$48a^3b^2+64a^2b^4+9a^4b^2$
$-917-\left(-93\right)$
$2xy'=y$
$x^2-y^2=81$
$-\left(-9\right)+\left(-20\right)-14-\left(-3\right)$
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