$\left(2b^2+3x\right)^5$
$\left(x-7\right)\frac{dy}{dx}=-2$
$2p^2+3p-pq$
$\lim_{x\to-2}\left(\frac{\left(\ln\left(3x+7\right)\right)}{x^2+3x+2}\right)$
$-5m+3-2v+10m-6+8v$
$45\cdot100$
$2x^2+21x=-40$
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