$48x^2-90x+192x-90$
$\frac{dx}{dt}=tx^3$
$\left(\frac{x^5+x^4+7x^2-27x\:+\:10}{x^2-x\:+\:5}\right)$
$2x+1>3$
$-5\left(-7d\right)$
$\left(m^2+4m\right)^4$
$\frac{x^2-2x+2}{x+1}$
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