$\int\frac{5\:}{x^2+8}dx$
$7x-41+4y-2z=0$
$\int\left(\frac{x^2-5x+3}{\left(x-1\right)\left(x-2\right)^2}\right)dx$
$\log\:\left(\frac{\sqrt{yz^5}}{x^3}\right)$
$y=2x^2-6x;\:x=-6$
$\frac{dy}{dx}=y\left(1+3x^2\right)$
$\left(9^2\right)^5\cdot\left(6^5\right)^2$
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