$\frac{3}{v}+\frac{1}{2}$
$5.38\cos\left(291.80\right)+5\sec\left(68.19\right)$
$\lim_{x\to\infty}\left(\frac{ln\left(7x+9\right)}{ln\left(9x+6\right)+10}\right)$
$m^3+15m^2+75m+125$
$\lim_{x\to\infty}\left(\frac{ln\left(2x\right)}{lnx}\right)$
$h\left(x\right)=\frac{x^2-3x}{x}$
$\left(-7+5\right)-\left(4-3\right)$
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