$\frac{dy}{dx}=5yx^2$
$0,05\:+0,005$
$\frac{dy}{dt}=-0.02y^2$
$\frac{dy}{dx}=15-3y$
$\frac { \frac { x } { 2 } } { 5 }$
$\int\left(\frac{-10}{4x^3}\right)dx$
$\int4x\left(\frac{5x^2}{3}-3\right)^5dx$
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