$\int\frac{x^4}{x^3+3x^2+4x+2}dx$
$x\left(x^2+x-1\right)=0$
$28v^2+24vz+8z^2$
$\:\left(x\:-\:3\right)\left(\:x\:-\:3\right)\:-\:\left(x\:-\:2\right)\left(x\:+\:5\right)$
$\left(3\right)-\left(-7\right)$
$\int3x\cdot\sqrt{4x+3}dx$
$5x-12+55-4x$
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