$\left(6\right)^4\left(15\right)^3$
$4a+3c-2b+5a+7b-8c$
$\frac{2}{2}+3-32^2+23^2$
$\left(5-\frac{4}{3}x\right)^3$
$44\cdot6$
$13^4$
$\left(4\right)^{8^1}$
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