$\frac{64n^3+m^3}{4+m}$

$\left(3m^2+4\right)\left(1m^2+1\right)$

$\log\left(x\right)=\log\left(x+3\right)-\log\left(x-1\right)$

$\int24\left(6x-7\right)^{-5}dx$

$g\left(x\right)=-1-x^5$

$\int x\left(1+cos\left(2x\right)\right)dx$

$\left(3x^2+6\right)\left(3x^2+4\right)$